Path With Minimum Effort
Problem Statement
You are given a grid of heights with rows rows and columns columns. You start in the top-left cell and want to reach the bottom-right cell. You may move up, down, left or right.
The effort of a route is the largest height difference between two neighbouring cells on it. Return the smallest effort over all routes.
Write int minimumEffortPath(vector<vector<int>>& heights) inside class Solution.
heights, a rows × columns grid of positive integers.
The smallest effort of any route from the top-left cell to the bottom-right cell.
The route 1, 3, 5, 3, 5 has steps 2, 2, 2, 2, so its effort is 2. The route 1, 2, 2, 2, 5 has a step of 3.
The route 1, 2, 3, 4, 5 has steps of 1 only.
There is a route through cells that all have height 1, with no step at all.
- • rows == heights.length
- • columns == heights[i].length
- • 1 ≤ rows, columns ≤ 100
- • 1 ≤ heights[i][j] ≤ 10^6
Pattern Recognition Clues
Recognising these key signals in the problem description immediately identifies the pattern:
Approach Complexity Ladder
Walk every route with backtracking; keep the smallest largest-step
Binary search the effort; check each candidate with one BFS over the cells
Min-heap over cells; a neighbour's effort is max(effort so far, step)
Walk every simple route from the top-left cell (never entering a cell already on the route). Carry the largest step seen so far along each walk. At the bottom-right cell, keep the smallest value among all routes.
Recognition rule for this sub-pattern:
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